泡利阻塞和纠缠解决了$Kπ$难题。$B^o \rightarrow Kπ$中的CP破坏; $B^{\pm} \rightarrow Kπ$衰变中没有
Pauli blocking and entanglement solve $Kπ$ puzzle. CP violation in $B^o \rightarrow Kπ$; not in $B^{\pm} \rightarrow Kπ$decays
摘要：
新的数据分析与泡利阻塞和纠缠解释了CP破坏在$B^o\rightarrow Kπ$衰变，在$B^{\pm} \rightarrow Kπ$衰变的缺席，并预测了意想不到的对比纯I=1/2在个人$B^{\pm}$和$B^o$最终状态和I=1/2违反之间的关系。对$B\rightarrow Kπ$数据的分析预测了这些观察到的同位旋关系，并解释了对旁观者夸克味的依赖。$B^+ \rightarrow Kπ$树形图$\bar b u\rightarrow \bar s u \bar u u$有两个相同的$u$夸克，分别来自弱顶点夸克和旁观者夸克。泡利原理要求这些短距离的夸克具有色或自旋反对称的波函数。守恒对称性的本征值在两个分离介子的终态中保持纠缠。这种泡利纠缠抑制了$B^+$衰变中的树企鹅干涉和CP破坏，但在有旁观者$d$夸克的$B^o$衰变中没有。即使在角动量为零的电荷共轭下，四体波函数也必须有两个对称性相同的反夸克与两个u夸克结合，才能碎裂成两个赝标介子态。它属于味SU（3）的27维表示，其中$ππ$态的同位旋I=2，相应的奇异态的V自旋V=2，奇异态是$Kπ$和$Kη_8$的线性组合。这些对称性即使在分离成两个介子后仍然纠缠在四体波函数中。强泡利抑制树过渡到$Kπ$只有一个小的V=2的分量，主要是V=1。没有泡利抑制过渡到I=2 $ππ$状态也有两个$u$夸克，但不同的颜色自旋耦合。$B^\pm\rightarrow Kπ$衰变中独立的颜色偏好和抑制树图的标准定义忽略了$uu$泡利纠缠。
英文摘要：
New data analysis with Pauli blocking and entanglement explains CP violation in $B^o\rightarrow Kπ$ decays, absence in $B^{\pm} \rightarrow Kπ$ decays and predicts unexpected contrast between pure I=1/2 in individual $B^{\pm}$ and $B^o$ final states and I=1/2 violation in relations between them. Analysis of $B\rightarrow Kπ$ data predicts these observed isospin relations and explains dependence on spectator quark flavor. $B^+ \rightarrow Kπ$ tree diagram $\bar b u\rightarrow \bar s u \bar u u$ has two identical $u$ quarks from weak vertex and spectator. The Pauli principle requires these quarks at short distances to have wave functions antisymmetric in color or spin. The eigenvalues of conserved symmetries remain entangled in a final state of two separated mesons. This Pauli entanglement suppresses tree-penguin interference and CP violation in $B^+$ decay but not in $B^o$ decay with spectator $d$ quark. The four-body wave function must have two antiquarks with the same symmetry combining with two u-quarks to fragment into a two-pseudoscalar-meson state even under charge conjugation with angular momentum zero. It is classified in the 27-dimensional representation of flavor SU(3) with isospin I=2 for the $ππ$ state and V spin V=2 for the corresponding strange state which is linear combination of $Kπ$ and $Kη_8$. These symmetries remain entangled in four-body wave function even after separation into two mesons. Strong Pauli suppression in tree transitions to $Kπ$ which has only a small V=2 component and is mainly V=1. No Pauli suppression in transitions to I=2 $ππ$ state with also two $u$ quarks but different color-spin couplings. Standard definition of independent color favored and suppressed tree diagrams in $B^\pm\rightarrow Kπ$ decays neglects $uu$ Pauli entanglement.
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