关于满足(x^p,x^q,x^r)=0的有限维绝对值代数
On finite-dimensional absolute-valued algebras satisfying (x^p,x^q,x^r)=0
摘要:
利用代数lH [Ra 99]的主同位素lH(a,b),我们给出了对固定整数p,q,r \in \{1,2\}满足(x^p,x^q,x^r)= 0的所有四维绝对值代数的一个详尽而不重复的描述.对于这样一个代数,同构类的个数N(p,q,r)是2或3,或者是无限的。具体1。N(1,1,1)=N(1,1,2)=N(1,2,1)=N(2,1,1)=2,2. N(1,2,2)=N(2,2,1)=3,3. N(2,1,2)=N(2,2,2)= \infty。此外,上述代数中的每一个都含有2维子代数。然而,第八维度的问题远未完全解决。事实上,存在8维绝对值代数,不包含4维子代数,满足(x^2,x,x^2)=(x^2,x^2,x^2)=0。
英文摘要:
By means of principal isotopes lH(a,b) of the algebra lH [Ra 99] we give an exhaustive and not repetitive description of all 4-dimensional absolute-valued algebras satisfying (x^p, x^q, x^r) = 0 for fixed integers p, q, r \in\{1,2\}. For such an algebras the number N(p,q,r) of isomorphism classes is 2 or 3, or is infinite. Concretely 1. N(1,1,1)=N(1,1,2)=N(1,2,1)=N(2,1,1)=2, 2. N(1,2,2)=N(2,2,1)=3, 3. N(2,1,2)=N(2,2,2)=\infty. Besides, each one of the above algebras contains 2-dimensional subalgebras. However, the problem in dimension 8 is far from being completely solved. In fact, there are 8-dimensional absolute-valued algebras, containing no 4- dimensional subalgebras, satisfying (x^2,x,x^2)=(x^2,x^2,x^2)=0.
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