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arXiv 0909.2598math.NT
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a^n-b^n被n的幂整除

The divisibility of a^n-b^n by powers of n

Chris Smyth

摘要:

对于给定的整数a,b和j至少为1,我们确定整数n的集合,其中a^n-b^n可被n^j整除。对于j= 1,2,这个集合通常是无限的;我们明确地找到例外情况,其中a,b集合是有限的。对于j=2,我们使用Zsigmondy定理。当j至少为3且gcd(a,b)=1时,集合可能总是有限的;然而,这似乎很难证明。我们还证明,确定整数n的集合,其中a^n+b^n可被n^j整除,可以减少到上述集合。

英文摘要:

For given integers a,b, and j at least 1 we determine the set of integers n for which a^n-b^n is divisible by n^j. For j=1,2, this set is usually infinite; we find explicitly the exceptional cases for which a,b the set is finite. For j=2, we use Zsigmondy's Theorem for this. For j at least 3 and gcd(a,b)=1, the set is probably always finite; this seems difficult to prove, however. We also show that determination of the set of integers n for which a^n+b^n is divisible by n^j can be reduced to that of the above set.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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